For a load of 2,500 watts on a 208 volt, 3-phase circuit, what is the calculated current in amps?

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Multiple Choice

For a load of 2,500 watts on a 208 volt, 3-phase circuit, what is the calculated current in amps?

Explanation:
To determine the correct current in amps for a 2,500-watt load on a 208-volt, 3-phase circuit, you can use the formula for calculating current in a 3-phase power system, which is: \[ I = \frac{P}{\sqrt{3} \times V} \] where: - \(I\) is the current in amps, - \(P\) is the power in watts (2,500 watts in this case), - \(V\) is the voltage in volts (208 volts). First, let's calculate the denominator: \[ \sqrt{3} \approx 1.732 \] Now substituting the values into the formula: \[ I = \frac{2500}{1.732 \times 208} \] Calculating the product of \(\sqrt{3}\) and \(208\): \[ 1.732 \times 208 \approx 360.256 \] Now substitute this back into the equation to find \(I\): \[ I = \frac{2500}{360.256} \approx 6.94 \text{ Amps} \] This calculation confirms that the current

To determine the correct current in amps for a 2,500-watt load on a 208-volt, 3-phase circuit, you can use the formula for calculating current in a 3-phase power system, which is:

[

I = \frac{P}{\sqrt{3} \times V}

]

where:

  • (I) is the current in amps,

  • (P) is the power in watts (2,500 watts in this case),

  • (V) is the voltage in volts (208 volts).

First, let's calculate the denominator:

[

\sqrt{3} \approx 1.732

]

Now substituting the values into the formula:

[

I = \frac{2500}{1.732 \times 208}

]

Calculating the product of (\sqrt{3}) and (208):

[

1.732 \times 208 \approx 360.256

]

Now substitute this back into the equation to find (I):

[

I = \frac{2500}{360.256} \approx 6.94 \text{ Amps}

]

This calculation confirms that the current

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